LAMPIRAN. Li4Ti5O12 + 6H2O

Transkripsi

1 6 LAMPIRAN Lampiran. Perhitungan Massa Bahan LiTiO Persamaan Stoikiometri: LiOH.HO + TiO LiTiO + 6HO Diketahui massa atom relatif masing-masing unsur adalah: Ar. Li = 6,9; Ar.O = 6; Ar.H =,008; Ar.Ti = 7,87 Massa LiTiO = 0 gram Maka berat molekul dari masing-masing bahan adalah: Mr. LiOH.HO = x Ar.Li + x Ar.O + x Ar.H = (6,9) + (6) + (,008) =,96 gr/mol Mr. TiO = x Ar.Ti + x Ar.O = (7,87) + (6) = 79,87 gr/mol Mr. LiTiO = x Ar.Li + x Ar.Ti + x Ar.O = (6,9) + (7,87) + (6) = 9, gr/mol Menghitung jumlah mol LiTiO Mol = = Massa LiTiO Mr LiTiO 0 gr 9, gr/mol = 0, mol Menghitung massa LiOH.HO Perhitungan mol LiOH.HO

2 7 mol LiOH.HO mol LiTiO = Koef.LiOH.HO Koef.LiTiO Mol LiOH.HO = x 0, mol Mol LiOH.HO = 0,08708 mol Perhitungan massa LiOH.HO Massa LiOH.HO = mol LiOH.HO x Mr. LiOH.HO = 0,08708 mol x,96 gr/mol =,667 gram Menghitung massa TiO Perhitungan mol TiO mol TiO = Koef.TiO mol LiTiO Koef.LiTiO Mol TiO = x 0, mol = 0,0890 mol Perhitungan masa TiO Massa TiO = mol TiO x Mr. TiO = 0,0890 mol x 79,87 gr/mol = 8, gram Lampiran. Perhitungan Penurunan Massa LiTiO Persamaan Stoikiometri: LiOH.HO + TiO LiTiO + 6HO Massa LiOH.HO =,667 gram Massa TiO = 8, gram Massa LiTiO = 0 gram

3 8 Penurunan massa LiTiO = (massa LiOH.HO+massa TiO) massa LiTiO massa LiOH.HO+massa TiO = (,667+8,698776) 0,667+8, =,797,797 = 9% x 00% x 00% x 00% Lampiran. Perhitungan Komposisi Lembaran LTO PTFE AB 8% 0% % 8% LTO = gram 0% PTFE = 0 x gram = 0,76 gram 8 % AB = x gram = 0,08 gram 8 Jadi total keseluruhan 00% = + 0,76 + 0,08 =,76 gram Maka: 8% LTO = 8 x,76 = gram 00 0% PTFE = 0 x,76 = 0,76 gram 00 % AB = x,76 = 0,08 gram 00 Lampiran. Perhitungan (XRD) a = a = λ sin Ɵ λ sin θ (h + k + l ) (h + k + l ) / a = parameter kisi (A o ) λ = panjang gelombang Cu Kα =, A 0

4 9 h,k,l = bidang kristal λ=, Aº ; * Bidang kristal (,,) Ɵ = 8,º Ɵ = 9,6 a = (,) x ( + + ) sin (9,6) = 7,8 x 0,06 = 7,8 0,0787 = 70, a = 70, a = 8,7 Aº Bidang kristal (,0,0) Ɵ =,; Ɵ =,6 a = (,) x ( ) sin (,6) = 7,96 x 0,7 = 7,96 0,08908 = 69, a = 69, a = 8,6 Aº Bidang kristal (,,) Ɵ =,7; Ɵ = 7,78

5 0 a = (,) x ( + + ) sin (7,78) = 6,0876 x 0,099 = 6,0876 0,7890 = 69,90068 a = 69,90068 a = 8,6 Aº Nilai h + k + l untuk kisi kubik Primitive,,,,,6,7,8,9,0,,,,... Body-centered,,6,8,0,,,6... Face-centered,,8,,,6,9,0,,7,... d = a (h + k + l ) / d= jarak bidang

6 Lampiran Perhitungan CV. Menghitung Tegangan Polarisasi Sampel V oks (Volt) V red (Volt) Ip (ma) 0 o C,79,,66 0 o C,78,,0 70 o C,78,9 0,9 Pada sampel 0 o C Vpolarisasi = Voksidasi Vreduksi =,79 V, V = 0, V Pada sampel 0 o C Vpolarisasi = Voksidasi Vreduksi =,78 V, V = 0,6 V Pada sampel 70 o C Vpolarisasi = Voksidasi Vreduksi =,78 V,9 V = 0,9 V. Menghitung Daya Listrik Pada sampel 0 o C P (mw) = Voksidasi x Ip =,79 x,66

7 =,97 mw Pada sampel 0 o C P (mw) = Voksidasi x Ip =,78 x,0 =,6 mw Pada sampel 70 o C P (mw) = Voksidasi x Ip =,78 x 0,9 = 0,87 mw. Menghitung besar koefisien difusi Ip, n A C V koefisien difusi (m /s) n = jumlah elektron per molekul yang berpindah selama proses interkalasi (untuk LTO = ) A = luas permukaan anoda = πr =, x (0,6) = 0,00096 cm C = konsentrasi ion lithium didalam padatan (,7x0 - mol.cm ) V= kecepatan scan rate (0, mv/s = 0 - V/s) Pada sampel 0 o C

8 Ip, n A C V (,66.0 ),69 x 0 0 x x 0,00096 x (,7.0 ) x 0, ,6 x 0 0 x, x,08.0 x 9, x 0, ,7 x 0,6 x 0 - m /s Pada sampel 0 o C Ip, n A C V (,0.0 ),69 x 0 0 x x 0,00096 x (,7.0 ) x 0,.0 6 7,6 x 0 0 x, x,08.0 x 9, x 0, ,7 x 0 0,9869 x 0 - m /s Pada sampel 70 o C Ip, n A C V (0,9.0 ),69 x 0 0 x x 0,00096 x (,7.0 ) x 0

9 0,.0 6 7,6 x 0 0 x, x,08.0 x 9, x ,7 x 0 0,0998 x 0 - m /s

10 LAMPIRAN 6 ALAT DAN BAHAN PERCOBAAN Beaker Glass dan Cawan Mortar dan Tumbukannya Timbangan Digital Glove Box Magnetic Stirrer Casing Coin Cell

11 6 Oven Tempat Pengeringan Bahan Hot Plate HS 6 Pisau ukur mesin coating Doctor Blade Mesin coating MSK III Bola Milling

12 7 Cruisible Planetary Ball Miller Ayakan 00 mesh Pipet tetes Oven STA

13 8 Furnace Serbuk LTO PTFE

14 Jan, 07 :8 PM (DELL) Status Primary QM: Star Pressure/Temperature: Ambient Chemical Formula: Li Ti O Empirical Formula: Li O Ti Weight %: Li6.0 O.8 Ti. Atomic %: Li9.0 O7. Ti.8 Compound Name: Lithium Titanium Oxide Radiation: CuKá λ:.0 Å d-spacing: Diff. Cutoff:.90 Intensity: Diffractometer SYS: Cubic SPGR: Fd-m (7) Author's Cell [ AuthCell a: 8.88() Å AuthCell Vol: 8.0 ų ] SS/FOM: F(9) = 6.(0.00, 6) Temp: 98.0 K (Author provided temperature) Space Group: Fd-m (7) Molecular Weight: 9.6 Crystal Data [ XtlCell a: 8.9 Å XtlCell b: 8.9 Å XtlCell c: 8.9 Å XtlCell α: XtlCell β: XtlCell γ: XtlCell Vol: 8.0 ų ] Crystal Data Axial Ratio [ a/b:.000 c/b:.000 ] Reduced Cell [ RedCell a:.9 Å RedCell b:.9 Å RedCell c:.9 Å RedCell α: RedCell β: RedCell γ: RedCell Vol: 6.0 ų ] Crystal (Symmetry Allowed): Centrosymmetric Subfile(s): Ceramic (Microwave), Inorganic Cross-Ref PDF #'s: Entry Date: 09/0/999 Pearson Symbol: cf? (Alternate), (Alternate), (Primary), (Alternate), (Alternate), (Primary) References: Type Primary Reference DOI Reference Tsubone, D., Hashimoto, T., Igarashi, K., Shimizu, T. J. Ceram. Soc. Jpn. Inter. Ed. 0, 79 (99). Database Comments: Sample Preparation: Prepared from ''Li C O'' and ''Li Ti O7'' at 90 C for 0 hours, followed by cooling in air. Temperature of Data Collection: Pattern taken at 98 K. Unit Cell Data Source: Powder Diffraction. d-spacings (9) - Li Ti O (Stick, Fixed Slit Intensity) - Cu Kα.06 Å θ ( ) d (Å) I h k 0 l 0 0 * θ ( ) d (Å) I 7 h 6 7 k l 0 * θ ( ) d (Å) I h k 0 6 l 0 0 * 07 International Centre for Diffraction Data. All rights reserved. Page /